Answer:
- [tex]\frac{27}{7}[/tex]
Step-by-step explanation:
Given
f(x) = [tex]\frac{3}{x+2}[/tex] - [tex]\sqrt{x-3}[/tex]
Evaluate f(19) by substituting x = 19 into f(x)
f(19) = [tex]\frac{3}{19+2}[/tex] - [tex]\sqrt{19-3}[/tex]
= [tex]\frac{3}{21}[/tex] - [tex]\sqrt{16}[/tex]
= [tex]\frac{1}{7}[/tex] - 4
= [tex]\frac{1}{7}[/tex] - [tex]\frac{28}{7}[/tex] = - [tex]\frac{27}{7}[/tex]
