Answer with Step-by-step explanation:
Since we have given that
[tex]BA=I[/tex]
As we know that
AA⁻¹ = I (A is invertible matrix)
Multiplying A⁻¹ on the both the sides:
[tex]BAA^{-1}=IA^{-1}\\\\B=A^{-1}[/tex]
Using the above result, we get that
[tex]BA=I=AA^{-1}\\\\BA=AB[/tex]
Therefore, BA = AB
Hence, proved.
