Answer with Step-by-step explanation:
Since we have given that
AB = 0 and A is invertible so, AA⁻¹ = I
So, Consider,
[tex]AB=0[/tex]
Multiplying A⁻¹ on both the sides, we get that
[tex]A^{-1}AB=A^{-1}0\\\\(AA^{-1})B=0\\\\IB=0\\\\B=0[/tex]
Hence proved.
