kingchris9540 kingchris9540

20-07-2019
Engineering

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The specific gravity of a fluid with a weight density of 31.2 lb/ft is a. 2.00 b. 0.969 c. 0.500 d. 1.03

Respuesta :

A1peakenbe A1peakenbe

23-07-2019

Answer:

Answer is c 0.500

Explanation:

[tex]SpecificGravity=\frac{\rho _{fluid}*g}{\rho _{water}*g}[/tex]

We know that [tex]\rho_{water}=62.42lb/ft^{3}[/tex]

Applying values we get

[tex]SpecificGravity=\frac{31.2}{62.4}=0.5[/tex]

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