Answer:
[tex]\large\boxed{y=\dfrac{2}{3}x-4}[/tex]
Step-by-step explanation:
[tex]2x-3y=12\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\2x-2x-3y=12-2x\\\\-3y=12-2x\qquad\text{divide both sides by (-3)}\\\\\dfrac{-3y}{-3}=\dfrac{12}{-3}+\dfrac{-2x}{-3}\\\\y=-4+\dfrac{2}{3}x[/tex]
