Answer:
T = 2.84 s
Explanation:
Time period of simple pendulum is given as
[tex]T = 2\pi \sqrt{\frac{L}{g}[/tex]
here we know that
[tex]L = 2 m[/tex]
[tex]g = 9.81 m/s^2[/tex]
now plug in all data in above equation
[tex]T = 2\pi \sqrt{\frac{2}{9.81}}[/tex]
[tex]T = 2.84 s[/tex]
so the time period of simple pendulum above the earth surface is approximately 2.84 s
