Answer:
Step-by-step explanation:
Put x = -8 to the formula of h(x)
[tex]h(x)=\dfrac{x^2+3x}{4x+27}\\\\h(-8)=\dfrac{(-8)^2+3(-8)}{4(-8)+27}=\dfrac{64-24}{-32+27}=\dfrac{40}{-5}=-8[/tex]
