Respuesta :
The answer is Gay-Lussacâs law.
Let's express all of these laws, using constant k, pressure P, temperature T, and volume V:
Boyle's law: PV = k
Charles law: V = kT
Daltonâs law: P = Pâ + Pâ + Pâ + ...
Gay-Lussacâs law: PV = kT
So, the only law that includes both pressure P and temperature T of a gas is Gay-Lussacâs law. We can check this hypothesis by using fictive values for each member of an equation.
For example, if
Pâ = ?
V = 6
k = 3
Tâ = 4
then PâV = kTâ
â PâĂ6 = 3Ă4
â Pâ = 12á6
â Pâ = 2
When we double the temperature:
Tâ = 2ĂTâ
â Tâ = 2Ă4
â Tâ = 8
Then:
PâV = kTâ
â Pâ à 6 = 3 à 8
â Pâ = 24 á 6
â Pâ = 4
If Pâ/Pâ = 4/2 = 2, this means that doubling temperature will double the pressure of the gas.
Let's express all of these laws, using constant k, pressure P, temperature T, and volume V:
Boyle's law: PV = k
Charles law: V = kT
Daltonâs law: P = Pâ + Pâ + Pâ + ...
Gay-Lussacâs law: PV = kT
So, the only law that includes both pressure P and temperature T of a gas is Gay-Lussacâs law. We can check this hypothesis by using fictive values for each member of an equation.
For example, if
Pâ = ?
V = 6
k = 3
Tâ = 4
then PâV = kTâ
â PâĂ6 = 3Ă4
â Pâ = 12á6
â Pâ = 2
When we double the temperature:
Tâ = 2ĂTâ
â Tâ = 2Ă4
â Tâ = 8
Then:
PâV = kTâ
â Pâ à 6 = 3 à 8
â Pâ = 24 á 6
â Pâ = 4
If Pâ/Pâ = 4/2 = 2, this means that doubling temperature will double the pressure of the gas.