Answer:
The final temperature of the water will be 328.81 K .
Explanation:
Using the equation, q = mcΔT
here, q = energy
m= mass
c= specific heat capacity
ΔT= change in temperature
Mass of water = 1kg (1000 g ) per liter
∴ 6.2 Liter of water = 6200 g
c of water ≈ 4.18 J /g/K
Now,
980000 = 6200*4.18*ΔT
ΔT = 37.81 K
∴ final temperature of the water = 291 + 37.81 = 328.81 K
