Answer:
See explanation
Step-by-step explanation:
The given function is [tex]f(x)=-(x+2)^2-1[/tex]
You could observe that: [tex]a=-1[/tex] when you compare to [tex]f(x)=a(x+h)^2+k[/tex].
This should tell you that the graph should open downwards.
Let us substitute [tex]x=3[/tex], to get: [tex]f(2)=-(3+2)^2-1=-5^2-1=-26[/tex]
Also when x=4,[tex]f(4)=-(4+2)^2-1=-6^2-1=-36-1=-37[/tex]
All the results are negative so the graph should appear below the x-axis
This shows that AJ made a mistake in the graph.
