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A rectangular packet of drink has a width that is 2 cm less than its length.
Its height is 4 cm more than its length.
(a) It is given that the length of the packet is m cm. Write down an expression,
in terins of m, for the total surface area of the packet.
[2]​

Respuesta :

kudzordzifrancis

Answer:

[tex]6m^2+8m-16[/tex]

Step-by-step explanation:

Given that the length of the packet is [tex]l=m[/tex] cm.

Then the width being 2cm less than the length becomes [tex]w=m-2[/tex] and the height being 4 cm more than its length becomes [tex]h=m+4[/tex]

The total surface area of the rectangular packet is given by:

[tex]T.S.A=2(lw+lh+wh)[/tex]

[tex]\implies T.S.A=2[m(m-2)+m(m+4)+(m-2)(m+4)][/tex]

We expand to get:

[tex]\implies T.S.A=2(m^2-2m+m^2+4m+m^2+4m-2m-8))[/tex]

[tex]\implies T.S.A=2(3m^2+4m-8)=6m^2+8m-16[/tex]

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