Answer:
[tex]\frac{2x^4+6x-5}{x^2+4}=2x^2-8+\frac{6x+27}{x^2+4}[/tex]
Step-by-step explanation:
We want to solve [tex]\frac{2x^4+6x-5}{x^2+4}[/tex] using long division.
We carry out the long division as shown in the attachment.
This implies that:
[tex]\implies \frac{2x^4+6x-5}{x^2+4}=2x^2-8+\frac{6x+27}{x^2+4}[/tex]
