Answer:
[tex]y = - \frac{3}{2}x + 2[/tex]
Step-by-step explanation:
Assuming the question wants you to write and equation passing through (2,-1); and parallel to y=-3/2x+6.
Then we use the slope intercept form:
[tex]y-y_1=m(x-x_1)[/tex]
We substitute the point and slope to get:
[tex]y - - 1 = - \frac{3}{2} (x - 2)[/tex]
[tex]y + 1 = - \frac{3}{2}x - + 3[/tex]
[tex]y = - \frac{3}{2}x + 3 - 1[/tex]
[tex]y = - \frac{3}{2}x + 2[/tex]
Note that parallel lines have the same gradient.
