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A person invested $6,000, some at 7% and the rest at 5%. The income from the 7% investment is equal to the income from the 5% investment. Find the number of dollars invested at each rate.

Respuesta :

jjguerrerom

Answer:

The person invested $3500 at 7% and $2500 at 5%

Step-by-step explanation:

We can say that [tex]0,07x+0,05x=6000[/tex] because the investment is equal both in one as in another, where x is the income from the investment.

Solving the equation we have:

[tex]0,12x=6000\\x=50000[/tex]

Then to get the incomes:

At 7%: [tex]I=0.07*50000\\I=$3500[/tex]

And at 5%: [tex]I=0.05*50000\\I=$2500[/tex]

Finally we can demonstrate the answer because the  income at 7% + income at 5% are 3500+2500=$6000

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