Answer:
n=1.18 x 10¹⁹
Explanation:
Given that
Current in the wire ,I = 1.9 A
The charge =q = n e
We know that
[tex]I=\dfrac{q}{t}[/tex]
I=Current
q=Charge
t=time
[tex]t=\dfrac{q}{I}[/tex]
Now by putting the values in the above equation we get'
q= 1.9 x 1 C
q= 1.9 C
q= n e
[tex]n=\dfrac{1.9}{1.602\times 10^{-19}}[/tex]
n=1.18 x 10¹⁹
