Answer:
[tex]\frac{7-x}{2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{21x-3x^2}{6x}[/tex] ← take out 3x from each term on the numerator
= [tex]\frac{3x(7-x)}{6x}[/tex] ← cancel 3x and 6x on the numerator/ denominator by 3x
= [tex]\frac{1(7-x)}{2}[/tex]
= [tex]\frac{7-x}{2}[/tex]
