Answer:
- -1 — does not cross
- 0 — does not cross
- 2 — crosses
Step-by-step explanation:
P(x) = x^4(x -2)^3(x +1)^2 has zeros at ...
- -1 — multiplicity 2 (does not cross)
- 0 — multiplicity 4 (does not cross)
- 2 — multiplicity 3 (crosses)
The zeros that have even multiplicity are points where the graph does NOT cross the x-axis. This is true because an even power of a number does not change sign when the sign of the number changes.
