Answer:
39,5 grams should be obtained of NaCl
Explanation:
We calculate the weight of 1 mol of NaCl:
Weight 1 mol NaCl= Weight Na + Weight Cl= 23g + 35,5g=58,5 g/mol
4,5M--> 4,5 moles NaCl in 1000ml (1L) of solution
1000ml-----4,5 moles NaCl
150 ml------x=(150 mlx4,5 moles NaCl)/1000ml=0,675 moles NaCl
1 mol NaCl--------------58,5 grams
0,675molesNaCl---x= (0,675molesNaClx58,5 grams)/1 mol NaCl
x= 39,4879 grams
