Option B:
Point B approximates [tex]\sqrt{15}[/tex].
Solution:
Let us first find the approximate value of [tex]\sqrt{15}[/tex].
[tex]\sqrt{15}=3.87[/tex]
In the number line 3.87 lies between 3 and 4.
So that [tex]\sqrt{15}[/tex] lies between 3 and 4.
Look at the given number line.
Point B lies between 2 and 4.
Hence point B approximates [tex]\sqrt{15}[/tex].
Option B is the correct answer.
