1+sec²x sin²x=
1+(1/cos²x) sin²x=
1+sin²x / cos²x=
(cos²x + sin²x)/cos²x=
1/cos²x=
sec²x
Answer:
1 + sec2x sin2x = sec2x
Step-by-step explanation:
1+ Sec²x (1 - cos²x) = 1+ Sec²x (1 - [tex]\frac{1}{sec^{2}x }[/tex]) = 1+ Sec²x -1 =Sec²x
