Answer:
Heat required to raise the temperature of ice is given as
[tex]Q = 2.39 \times 10^6 J[/tex]
Explanation:
Heat required to raise the temperature of the object is given as
[tex]Q = mL + ms(\Delta T)[/tex]
here we know that
m = 3.84 kg
L = 335000 J/kg[/tex]
s = 4186 J/C K
now we have
[tex]Q = 3.84 (335000) + 3.84(4186)(68.5 - 0)[/tex]
[tex]Q = 1.29 \times 10^6 + 1.1\times 10^6[/tex]
[tex]Q = 2.39 \times 10^6 J[/tex]
