Respuesta :

konrad509
[tex]x^3 + x^2 - 20x=0\\ x(x^2+x-20)=0\\ x(x^2+5x-4x-20)=0\\ x(x(x+5)-4(x+5))=0\\ x(x-4)(x+5)=0\\ x=0 \vee x=4 \vee x=-5[/tex]

Answer:

B. 0, −5, 4

Step-by-step explanation:

Given :


[tex]x^{3} +x^{2} -20x[/tex]


Solution:


[tex]x^{3} +x^{2} -20x[/tex]


taking x common from the given polynomial


⇒[tex]x(x^{2} +x-20)=0[/tex]


⇒[tex]x(x(x+5)-4(x+5))=0[/tex]


⇒[tex]x(x+5)(x-4)=0[/tex]


⇒ x=0 , x+5=0 , x-4=0


⇒x = 0 , x = -5 , x = 4


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