Respuesta :

[tex]a=5m;\ H=13m\\\\The\ volume\ of\ a\ square\ pyramid:V=\frac{1}{3}a^2H\\\\Subtitute\ the\ values\ of\ a\ and\ H:\\\\\boxed{V=\frac{1}{3}\cdot5^2\cdot13=\frac{1}{3}\cdot25\cdot13=\frac{325}{3}=108\frac{1}{3}\ (m^3)}[/tex]

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