Step-by-step explanation:
[tex](x - 4)(x + 2) = 16 \\ {x}^{2} + (- 4 + 2)x + ( - 4) \times 2= 16 \\ {x}^{2} - 2x - 8 - 16 = 0 \\ {x}^{2} - 2x - 24 = 0 \\ is \: the \: standard \: form.[/tex]
Answer:
(x-4)(x+2)=16
[tex]x^{2}[/tex]+(-4+2)x+(-4)×2=16
[tex]x^{2}[/tex] - 2x - 8 - 16= 0
[tex]x^{2}[/tex] -2x -24 = 0
