Answer:
[tex]m\angle ABC=46^o[/tex]
Step-by-step explanation:
step 1
we know that
The inscribed angle is half that of the arc it comprises.
so
[tex]m\angle ADC=\frac{1}{2}(arc\ AC)[/tex]
we have
[tex]m\angle ADC=23^o[/tex]
so
[tex]23^o=\frac{1}{2}(arc\ AC)\\arc\ AC=46^o[/tex]
step 2
we know that
Central angle is the angle that has its vertex in the center of the circumference and the sides are radii of it
so
[tex]m\angle ABC=arc\ AC[/tex] ----> by central angle
therefore
[tex]m\angle ABC=46^o[/tex]
