Respuesta :

caylus
Hello,

Let's assume

[tex]u=z+ \dfrac{1}{z} \\ u^2=(z+ \dfrac{1}{z} )^2=z^2+2*z* \dfrac{1}{z} + \dfrac{1}{z^2} =34+2=36\\ ==\ \textgreater \ \ u=6\\ (z+ \dfrac{1}{z} )^3=(z+ \dfrac{1}{z} )(z^2+z* \frac{1}{z} + \frac{1}{z^2} )\\ =6*(34+1)=210 [/tex]