Answer:
√33 ≈ 5.7
Step-by-step explanation:
The length of the bottom diagonal is given by pythagoras, let's call it d:
[tex]d =\sqrt{5^2+2^2}[/tex]
Then, the length of the diagonal through the box is also given by pythagoras as:
[tex]\sqrt{d^2 + 2^2}[/tex]
In total, that is:
[tex]\sqrt{5^2 + 2^2 + 2^2} = \sqrt{33} \approx 5.7[/tex]
