We have four rectangular faces that are all different (but all width 30), and two congruent trapezoid ends.
The rectangles are top 12×30, right, 26×30, left 25×30, bottom 29×30
Area of trapezoid is average of the bases times height,
(1/2)(12 + 29)(24)
We have two of those. Let's add everything up; we can factor out a 30 on the rectangles.
A = 30(12 + 26 + 25 + 29) + 2(1/2)(12 + 29)(24) = 3744
Answer: 3744 sq cm
