Respuesta :

devishri1977

Answer:

Step-by-step explanation:

[tex]\frac{x +7}{x+3}+\frac{x-4}{3}=\frac{(x+7)*3}{(x+3)*3}+\frac{(x-4)(x+3)}{3(x+3)}\\\\=\frac{(x+7)*3+(x-4)(x+3)}{3(x+3)}\\\\=\frac{3x+21+x^{2}+3x-4x -12}{3x +9}\\\\=\frac{x^{2}+2x-12}{3x+9}\\\\[/tex]

spiderman120

Answer:

I hope this helps you thanks

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