Answer:
[tex]\frac{1}{6} s^{3}[/tex]
Step-by-step explanation:
[tex]\frac{8}{9} s^{3-1} *\frac{6}{32} s^{2-1}[/tex]
[tex]\frac{8}{9} s^{2} *\frac{6}{32} s^{1}[/tex]
[tex]\frac{8}{9} s^{2} *\frac{3}{16} s[/tex]
[tex]\frac{24}{144} s^{2+1}[/tex]
[tex]=\frac{1}{6} s^{3}[/tex]
