lalla69
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  • 17-06-2020
  • Mathematics
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Find the sum of 6(1-a^2), -2(3-a+2a^2) and 5(-2a+3a^2)​

Respuesta :

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09pqr4sT 09pqr4sT
  • 17-06-2020

Answer:

[tex]5a^2-8a[/tex]

Step-by-step explanation:

[tex]6(1-a^2)-2(3-a+2a^2)+5(-2a+3a^2)[/tex]

[tex](6)(1)+(6)(-a^2)+(-2)(3)+(-2)(-a)+(-2)(2a^2)+(5)(-2a)+(5)(3a^2)[/tex]

[tex]6+-6a^2+-6+2a+-4a^2+-10a+15a^2[/tex]

[tex](-6a^2+-4a^2+15a^2)+(2a+-10a)+(6+-6)[/tex]

[tex]5a^2-8a[/tex]

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