Respuesta :

aegina
  • y^2+9y+20
  • y^2+10y+21
  • y^2+2y+3
  • Step-by-step explanation:
  1. (y+5(y+4) =y(y+4)+5(y+4) =y^2+4y+5y+20 =y^2+9y+20
  2. (y+3(y+7) =y(y+7)+3(y+7) =y^2+7y+3y+21 =y^2+10y+21
  3. (y+3)(y-1)

=y(y-1)+3(y-1)

=y^2-y+3y-3

= y^2+2y+3

Answer:

y^2+2y+3

Step-by-step explanation:

you just need to use the distributive property.

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