Answer:
Step-by-step explanation:
[tex]\frac{5}{6}x-1>1\frac{1}{3}\\\\\frac{5}{6}x-1>\frac{4}{3}\\\\\frac{5}{6}x>\frac{4}{3}+1\\\\\frac{5}{6}x>\frac{4}{3}+\frac{3}{3}\\\\\frac{5}{6}x>\frac{7}{3}\\\\x>\frac{7}{3}*\frac{6}{5}\\\\x>\frac{7*2}{5}\\x>\frac{14}{5}\\\\x>2\frac{4}{5}[/tex]
