Answer:
x^2 + y^2 - 4x + 6y - 3 = 0
Step-by-step explanation:
(x-a)^2 + (y-b)^2 = r^2 is the equation of a circle which has center point (a,b) and radius r.
So in this question (2,-3) is the center and r=4.
Then we can write the equation as,
(x-2)^2 + (y+3)^2 = 16
x^2 + y^2 - 4x + 6y - 3 = 0
That is the Equation of the circle.
