Answer:
Option (2).
Step-by-step explanation:
It is given in the question,
ΔLMN is a right triangle with base LM = 3a units
Hypotenuse MN = 5a
By applying Pythagoras theorem in ΔLMN,
MN² = LM² + NM²
(5a)² = (3a)² + MN²
25a² - 9a² = MN²
MN = √16a²
MN = 4a
Therefore, vertices of the triangle will be L(0, 0), M(3a, 0) and N(0, 4a).
Option (2) will be the answer.
