Answer:
there are no zeros in f(x)
Step-by-step explanation:
[tex]f(x)=3x^2+9x+12\\\\f(x)=0\\\\0=3x^2+9x+12\\\\[/tex]
to know if the equation has real solutions we have to know if
[tex]b^2-4ac\geq 0[/tex]
a=3
b=9
c=12
[tex]9^2-4*3*12\\\\=81-144\\\\=-63[/tex]
so there aren't real solutions
hence there aren't any zeros in f(x)
