snyderd9885 snyderd9885
  • 17-08-2020
  • Mathematics
contestada

Find the absolute extrema of the function on the closed interval. f(x) = sin 2x, [0, 2π]

Respuesta :

oscar236
oscar236 oscar236
  • 17-08-2020

Answer:

Minimum -1, maximum 1.

At points (3π/4. -1) and  (π/4 , 1)

Step-by-step explanation:

The maximum value for the sine of an angle is 1 and the minimum is -1.

The angle will have values of π/2 and 3π/2 at these points.

As the angle is 2x the angle values will be  π/4 and  3π/4.

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