Answer:
20[tex]\sqrt{3}[/tex]
Step-by-step explanation:
The diagonal splits the square into 2 right triangles
Using Pythagoras' identity on one of the right triangles
With legs 10[tex]\sqrt{6}[/tex] and hypotenuse the diagonal d, then
d² = (10[tex]\sqrt{6}[/tex] )² + (10[tex]\sqrt{6}[/tex] )² = 600 + 600 = 1200 ( take square root of both sides )
d = [tex]\sqrt{1200}[/tex] = [tex]\sqrt{400(3)}[/tex] = [tex]\sqrt{400}[/tex] × [tex]\sqrt{3}[/tex] = 20[tex]\sqrt{3}[/tex]
