Answer : [tex]a_{n+1}=a_n+8[/tex]
Step-by-step explanation:
The given explicit formula : [tex]a_n=8n-3[/tex] , where n is a natural number.
At n=1 , [tex]a_1=8-3=5[/tex]
At n=2, [tex]a_2=8(2)-3=16-3=13[/tex]
At n=3 , [tex]a_3=8(3)-3=24-3=21[/tex]
We can see the common difference is 8.
So we can write [tex]a_{n+1}=a_n+8[/tex]
Hence, the recursive formula for the explicitly defined sequence is [tex]a_{n+1}=a_n+8[/tex]
