Answer:
87.5 kJ
Explanation:
The potential energy stored in a stretch spring is given by the expression below
PE = Work = force * distance
So:
[tex]PE = (kx) * x[/tex]
This then simplifies to:
[tex]PE = kx^2[/tex]
where k is the spring constant= 140 N/m
Given that x= 25 m
Substituting our data into the expression for P.E stored we have
[tex]PE = 140*25^2\\\\PE= 140*625\\\\PE= 87500 J[/tex]
Hence the energy stored in the spring is 87.5kJ
