Respuesta :

unicorn3125

Answer:

              [tex]B=\dfrac{3T-S}{6P}[/tex]

Step-by-step explanation:

               [tex]{}\ \ S\ =\ 3T - 6PB\\^{+6PB}\quad\ ^{+6PB}\\\\S+6PB=3T\\{}\quad^{-S}\qquad\ \ ^{-S}\\\\6PB = 3T-S\\^{\div(6P)}\qquad^{\div(6P)}\\\\B=\dfrac{3T-S}{6P}[/tex]

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