Answer:
B(10, 6)
Step-by-step explanation:
If P is midpoint of AB and: [tex]A(0,\,0)\,,\quad P(5,\,3)\,,\quad B(x_B,\,y_B)[/tex]
then:
[tex]x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6[/tex]
