Given:
Length of B = 10 - 2 = 8
Length of A = 6
To Find:
The length of the segment AB.
Pythagoras Theorem:
[tex] \large \pink {\sf {{AB}^{2} = {AC}^{2} + {BC}^{2} }} [/tex]
Explanation:
[tex] \large \purple {\sf {{AB}^{2} = {6}^{2} + {8}^{2}}} [/tex]
[tex] \large \blue {\sf {or, \: {AB}^{2} = 36 + 64 = 100}} [/tex]
[tex] \large \red {\sf {or, \: AB = \sqrt{100} = 10}} [/tex]
Answer:
The length of the segment AB is 10.
Option D. 10 is the correct answer.
