Answer:
0
Step-by-step explanation:
Using the trigonometric identity
cotx = [tex]\frac{cosx}{sinx}[/tex]
Given
3cotθ = 2 , then
3[tex]\frac{coso}{sino}[/tex] = 2 ( multiply both sides by sinθ )
3cosθ = 2sinθ ( subtract 3cosθ from both sides )
2sinθ - 3cosθ = 0
Thus
[tex]\frac{2sin0-3cos0}{2sin0+3cos0}[/tex]
= [tex]\frac{0}{2sin0+3cos0}[/tex]
= 0
