Respuesta :

luana
[tex]Equation\ of\ circle\\\\\ r^2=(x-a)^2+(y-b)^2\\\\ a,b- \ coordinates\ of\ center\ of\ circle\\\\\ (a,b)=(2,-5) \\\\ r-\ radius\\\\ r=4\\\\Solution:\ 4^2=(x-2)^2+(y+5)^2\\\\\ [/tex]
konrad509
[tex](x-h)^2+(y-k)^2=r^2\\\\ (x-2)^2+(y+5)^2=16[/tex]

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