Answer:
cscA = [tex]\frac{5}{4}[/tex]
Step-by-step explanation:
Using the identity
csc x = [tex]\frac{1}{sinx}[/tex] , then
sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex] , thus
cscA = [tex]\frac{1}{\frac{4}{5} }[/tex] = [tex]\frac{5}{4}[/tex]
