Answer:
1567.09 N/m
Explanation:
Step one:
given data
mass m=5kg
compression x= 3.13cm to m= 0.0313m
According to Hooke's law, provided the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force
F=ke
where
k= spring constant in N/m
e= extension/compression in
Step two:
assume g= 9.81m/s^2
F=mg
F=5*9.81
F=49.05N
substitute in the expression F=ke
49.05=k*0.0313
k=49.05/0.0313
k=1567.09 N/m
The force constant (in N/m) of the spring is 1567.09 N/m
