Answer:
[tex]186.5\ \text{K}[/tex]
Explanation:
[tex]V_1[/tex] = Initial volume = 0.05 L
[tex]V_2[/tex] = Final volume = 0.1 L
[tex]T_1[/tex] = Initial temperature
[tex]T_2[/tex] = Final temperature = 373 K
From the ideal gas law we have
[tex]PV=nRT[/tex]
So
[tex]V\propto T[/tex]
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\Rightarrow T_1=\dfrac{V_1}{V_2}\times T_2\\\Rightarrow T_1=\dfrac{0.05}{0.1}\times 373\\\Rightarrow T_1=186.5\ \text{K}[/tex]
The intial temperature is [tex]186.5\ \text{K}[/tex].
