Answer:
2 + i
Step-by-step explanation:
Given
[tex]\frac{4+\sqrt{16-(4)(5)} }{2}[/tex]
= [tex]\frac{4+\sqrt{16-20} }{2}[/tex]
= [tex]\frac{4+\sqrt{-4} }{2}[/tex]
= [tex]\frac{4+2i}{2}[/tex]
= 2 + i
