Answer:
Q = 6583.5 J
Explanation:
Given data:
Heat required = ?
Mass of water = 35 g
Initial temperature = 50°C
Final temperature = 95°C
Solution:
Specific heat capacity of water is 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 95°C - 50°C
ΔT = 45°C
Q = 35 g×4.18 j/g.°C × 45°C
Q = 6583.5 J
